Ruby program to find the reverse of a given number using recursion

def reverse(num,rev)
    if num > 0 
        rem = (num % 10);
        rev = rev*10+rem;
        reverse(num / 10,rev);
    else
        return rev;    
    end
end

print "Enter number: ";
number = gets.chomp.to_i;  

result = reverse(number, 0);
print "Result is: ",result;

Output:

Enter number: 1234
Result is: 4321