Python program to search an element in a Circular Linked List
#Represents the node of list.
class Node:
def __init__(self,data):
self.data = data;
self.next = None;
class CreateList:
#Declaring head and tail pointer as null.
def __init__(self):
self.head = Node(None);
self.tail = Node(None);
self.head.next = self.tail;
self.tail.next = self.head;
#This function will add the new node at the end of the list.
def add(self,data):
newNode = Node(data);
#Checks if the list is empty.
if self.head.data is None:
#If list is empty, both head and tail would point to new node.
self.head = newNode;
self.tail = newNode;
newNode.next = self.head;
else:
#tail will point to new node.
self.tail.next = newNode;
#New node will become new tail.
self.tail = newNode;
#Since, it is circular linked list tail will point to head.
self.tail.next = self.head;
#Searches for a node in the list
def search(self,element):
current = self.head;
i = 1;
flag = False;
#Checks whether list is empty
if(self.head == None):
print("List is empty");
else:
while(True):
#Compares element to be found with each node present in the list
if(current.data == element):
flag = True;
break;
current = current.next;
i = i + 1;
if(current == self.head):
break;
if(flag):
print("Element is present in the list at the position : " + str(i));
else:
print("Element is not present in the list");
class CircularLinkedList:
cl = CreateList();
#Adds data to the list
cl.add(1);
cl.add(2);
cl.add(3);
cl.add(4);
#Search for node 2 in the list
cl.search(2);
#Search for node in the list
cl.search(7);
Output:
Element is present in the list at the position: 2
Element is not present in the list
