Java program to create a Circular Linked List of n nodes and display it in reverse order
public class ReverseList {
//Represents the node of list.
public class Node{
int data;
Node next;
public Node(int data) {
this.data = data;
}
}
//Declaring head and tail pointer as null.
public Node head = null;
public Node tail = null;
//This function will add the new node at the end of the list.
public void add(int data){
//Create new node
Node newNode = new Node(data);
//Checks if the list is empty.
if(head == null) {
//If list is empty, both head and tail would point to new node.
head = newNode;
tail = newNode;
newNode.next = head;
}
else {
//tail will point to new node.
tail.next = newNode;
//New node will become new tail.
tail = newNode;
//Since, it is circular linked list tail will point to head.
tail.next = head;
}
}
//Displays all the nodes in the list
public void display() {
Node current = head;
if(head == null) {
System.out.println("List is empty");
}
else {
do{
//Prints each node by incrementing pointer.
System.out.print(" "+ current.data);
current = current.next;
}while(current != head);
System.out.println();
}
}
//Reverse the order of the nodes present in the list.
public void reverse(Node current) {
//Checks if the next node is head, if yes then prints it.
if(current.next == head) {
System.out.print(" "+current.data);
return;
}
//Recursively calls the reverse function
reverse(current.next);
System.out.print(" "+current.data);
}
public static void main(String[] args) {
ReverseList cl = new ReverseList();
cl.add(1);
cl.add(2);
cl.add(3);
cl.add(4);
cl.add(5);
cl.add(6);
System.out.println("Original List: ");
cl.display();
System.out.println("Reversed List: ");
//Print reversed list
cl.reverse(cl.head);
}
}
Output:
Original List:
1 2 3 4 5 6
Reversed List:
6 5 4 3 2 1
