Program to print the next day’s date, month, year

#include <iostream>
using namespace std;

int main() {
  int d, m, y;
  cout << "Enter today's date in the format: DD MM YYYY\n";
  cin >> d >> m >> y;

  if (d > 0 && d < 28) {  // checking for day from 0 to 27
    d += 1;
  }
  if (d == 28) {
    if (m == 2) {  // checking for february
      if ((y % 400 == 0) || (y % 100 != 0 || y % 4 == 0)) {  // leap year check in case of feb
        d = 29;
      } else {
        d = 1;
        m = 3;
      }
    } else {  // when it's not feb
      d += 1;
    }
  }
  if (d == 29) {  // last day check for feb
    if (m == 2) {
      d = 1;
      m = 3;
    } else {
      d += 1;
    }
  }
  if (d == 30) {  // last day check for april, june, september, november
    if (m == 1 || m == 3 || m == 5 || m == 7 || m == 8 || m == 10 || m == 12) {
      d += 1;
    } else {
      d = 1;
      m += 1;
    }
  }
  if (d == 31) {  // last day of the month
    d = 1;
    if (m == 12) {  // checking for last day of the year
      y += 1;
      m = 1;
    } else {
      m += 1;
    }
  }

  cout << "Tomorrow's date:\n";
  if (d < 10) {  // checking if day needs to be preceded by 0
    cout << "0" << d << " ";
  } else {
    cout << d << " ";
  }
  if (m < 10) {  // checking if month needs to be preceded by 0
    cout << "0" << m << " ";
  } else {
    cout << m << " ";
  }
  cout << y;
  return 0;
}

Output:

Enter today's date in the format:DD MM YYYY
28 02 2020

Tomorrow's date:
01 03 2020