Python program to create a Circular Linked List of n nodes and display it in reverse order
#Represents the node of list.
class Node:
def __init__(self,data):
self.data = data;
self.next = None;
class CreateList:
#Declaring head and tail pointer as null.
def __init__(self):
self.head = Node(None);
self.tail = Node(None);
self.head.next = self.tail;
self.tail.next = self.head;
#This function will add the new node at the end of the list.
def add(self,data):
newNode = Node(data);
#Checks if the list is empty.
if self.head.data is None:
#If list is empty, both head and tail would point to new node.
self.head = newNode;
self.tail = newNode;
newNode.next = self.head;
else:
#tail will point to new node.
self.tail.next = newNode;
#New node will become new tail.
self.tail = newNode;
#Since, it is circular linked list tail will point to head.
self.tail.next = self.head;
#Displays all the nodes in the list
def display(self):
current = self.head;
if self.head is None:
print("List is empty");
return;
else:
#Prints each node by incrementing pointer.
print(current.data),
while(current.next != self.head):
current = current.next;
print(current.data),
#Reverse the order of the nodes present in the list.
def reverse(self, current):
#Checks if the next node is head, if yes then prints it.
if(current.next == self.head):
print(current.data),
return;
#Recursively calls the reverse function
self.reverse(current.next);
print(current.data),
class CircularLinkedList:
cl = CreateList();
#Adds data to the list
cl.add(1);
cl.add(2);
cl.add(3);
cl.add(4);
cl.add(5);
cl.add(6);
print("Original List: ");
cl.display();
print("\nReversed List: ");
#Print reversed list
cl.reverse(cl.head);
Output:
Original List:
1 2 3 4 5 6
Reversed List:
6 5 4 3 2 1
