Python program to create a Circular Linked List of N nodes and count the number of nodes
#Represents the node of the list.
class Node:
def __init__(self,data):
self.data = data;
self.next = None;
class CreateList:
#Declaring head and tail pointer as null.
def __init__(self):
self.count = 0;
self.head = Node(None);
self.tail = Node(None);
self.head.next = self.tail;
self.tail.next = self.head;
#This function will add the new node at the end of the list.
def add(self,data):
newNode = Node(data);
#Checks if the list is empty.
if self.head.data is None:
#If list is empty, both head and tail would point to new node.
self.head = newNode;
self.tail = newNode;
newNode.next = self.head;
else:
#tail will point to new node.
self.tail.next = newNode;
#New node will become new tail.
self.tail = newNode;
#Since, it is circular linked list tail will point to head.
self.tail.next = self.head;
#This function will count the nodes of circular linked list
def countNodes(self):
current = self.head;
self.count=self.count+1;
while(current.next != self.head):
self.count=self.count+1;
current = current.next;
print("Count of nodes present in circular linked list: "),
print(self.count);
class CircularLinkedList:
cl = CreateList();
#Adds data to the list
cl.add(1);
cl.add(2);
cl.add(4);
cl.add(1);
cl.add(2);
cl.add(3);
#Displays all the nodes present in the list
cl.countNodes();
Output:
Count of nodes present in circular linked list:
6
