Python program to check if the given number is a Disarium Number

#calculateLength() will count the digits present in a number    
def calculateLength(n):    
    length = 0;    
    while(n != 0):    
        length = length + 1;    
        n = n//10;    
    return length;    
     
num = 175;    
rem = sum = 0;    
len = calculateLength(num);    
     
#Makes a copy of the original number num    
n = num;    
     
#Calculates the sum of digits powered with their respective position    
while(num > 0):    
    rem = num%10;    
    sum = sum + int(rem**len);    
    num = num//10;    
    len = len - 1;    
     
#Checks whether the sum is equal to the number itself    
if(sum == n):    
    print(str(n) + " is a disarium number");    
else:    
    print(str(n) + " is not a disarium number");    

Output:

175 is a disarium number