Program to check if two strings are anagrams

#include <iostream>
#include<string>
using namespace std;
int isanagram(string str1,string str2)
{
int count1[26] = {0}, count2[26] = {0}, ascii, i = 0;
while (str1[i] != '\0')         //counting all alphabets in string 1
{
ascii=str1[i]-97;	//taking each character's ascii value and feeding it into the count array
count1[ascii]+=1;	//taking into assumption that the string is made of lower case chars only.
i++;
}
i = 0;
while (str2[i] != '\0')              //counting all alphabets in string 2
{
ascii=str2[i]-97;
count2[ascii]+=1;
i++;
}
for (i = 0; i < 26; i++) //comparing the count of chars in both strings
{
if (count1[i] != count2[i])
return 0;
}
return 1;
}
int main()
{
string str1,str2;
cout&lt;&lt;"Enter string 1\n";
getline(cin,str1);
cout&lt;&lt;"Enter String 2:\n";
getline(cin,str2);

if (isanagram(str1, str2)) //calling the anagram checking method
	printf("The strings are anagrams\n");
else
	printf("The strings are not anagrams\n");
return 0;

}

Output:

Optimistic case:

Enter string 1anagram
Enter String 2:nag a ram
The strings are anagrams

Pessimistic case:

Enter string 1hello
Enter String 2:world
The strings are not anagrams